First, we need to find the angular momentum of the top about its axis of rotation. We can use the concept of the moment of inertia and the angular velocity of the top.

focuses on . This chapter bridges the gap between particle kinetics and the more complex motion of rigid bodies by introducing rotational inertia and the Free-Body Diagram (FBD) / Kinetic Diagram (KD) method. 1. Fundamental Equations of Motion

The angular velocity of the top about its axis is:

If you can tell me from Chapter 16 you are struggling with, I can walk you through the step-by-step solution and explain the key concepts behind it. Alternatively, if you'd like, I can: Explain the difference between translation and rotation

vB=vA+ω×rB/Av sub cap B equals v sub cap A plus omega cross r sub cap B / cap A end-sub

I_z = mk^2 = 0.5 kg × (0.05 m)^2 = 0.00125 kg·m^2

Using the principles of three-dimensional motion of rigid bodies, we can solve this problem.

M_z = 0 (since the weight acts through the axis of symmetry)

r⃗B/Amodified r with right arrow above sub cap B / cap A end-sub

: Solving systems with multiple moving parts by drawing separate FBD/KD pairs for each component and solving the resulting equations simultaneously.